![](https://bossmaths.com/wp-content/uploads/mult.png)
Solution to (a)
\(47 \times 49 = 48 \times 49 – 1 \times 49\)\( = 2352 – 49 = 2303\)
Solution to (b)
\(48 = 2^4 \times 3\) and \(49 = 7^2\) so \(2352 = 2^4 \times 3 \times 7^2\)
Solution to (c)
Since \(2352\) is a multiple of \(48\), it is also a multiple of \(24\). Therefore the remainder when \(2353\) is divided by \(24\) is \(1\), so the time will be \(4.14 \text{pm}\).